Spring integration dsl outboundGateway set query parameter using expression

Question

I have a rest request in spring integration flow. How to pick the value from the payload or header from message and set the query parameter of url

.handle(Http.outboundGateway(UriComponentsBuilder.fromHttpUrl("localhost:8080).path("search").queryParam("order", "orderId").toUriString())
.httpMethod(HttpMethod.GET)
.expectedResponseType(Order.class))

In the above code, i need to fetch the orderId from payload

Answer 1

If you insist to use UriComponentsBuilder, then something like this:

.handle(Http.outboundGateway(m ->
        UriComponentsBuilder.fromHttpUrl("localhost:8080")
                    .path("search")
                    .queryParam("order", m.getPayload())
                    .build())
            .httpMethod(HttpMethod.GET)
            .expectedResponseType(Order.class))

Or like this:

.handle(Http.outboundGateway(m -> servieUrl + "/search?orderId={orderId}")
            .uriVariable("orderId", m -> m.getPayload())
            .httpMethod(HttpMethod.GET)
            .expectedResponseType(Order.class))