Printing bits in long long number (C++)

Question

I want to print all bits of a long long number. When I am doing it in main() everything is fine, but in printBits() function (where code is same) there is an extra 1 on 32th bit.

The code:

#include <iostream>

void printBits(long long number)
{
    std::cout<<number<<" -> ";
    for (char i=63; i>=0; --i)
    {
        std::cout<<(bool)(number&(1<<i));
    }
    std::cout<<std::endl;
}

int main()
{
    long long number=1;

    std::cout<<number<<" -> ";
    for (char i=63; i>=0; --i)
    {
        std::cout<<(bool)(number&(1<<i));
    }
    std::cout<<std::endl;

    printBits(number);

    return 0;
}

Result is:

1 -> 0000000000000000000000000000000000000000000000000000000000000001
1 -> 0000000000000000000000000000000100000000000000000000000000000001

Process returned 0 (0x0)   execution time : 0.012 s
Press any key to continue.

Answer 1

The literal 1 defaults to an integer. Cast it to long long to solve the problem.

std::cout<<(bool)(number&(((long long)1)<<i));