How to make the output of OS.popen command a list of choice menu?

Question

How to make the output of os.popen a list of choice menu options which will be used as input for another program?

Note - Every time the output varies we cannot define one constant choice menu. It can be more than 10 or sometimes less than 10 elements.

SG = "dzdo symaccess -sid {0} show {1} view -detail"
IG = os.popen SG).read()
print SG

Above is the program if the output of SG has some ten elements like below:

tiger
lion
elephant
deer
pigeon
fox
hyena
leopard
cheatah
hippo

The above elements I want to make as choice of elements like:

print("1. tiger")
print("2. lion")
print("3. elephant")
print("4. deer")
.
.
.
print("11. exit")
print ("\n")
choice = input('enter your choice [1-11] :')
choice = int(choice)
if choice ==1:
    ...

So how do we add each element in each print statement and make it have a choice option, and how can we know the number of elements and make the same number of choices menu?

Answer 1

Obviously I can't demonstrate the popen stuff, so I've hard-coded the input data into a multi-line string, which I turn into a list using the .splitlines method. This code will cope with data of any size, it's not restricted to 10 items.

It does some primitive checking of the user input, a real program should display a more helpful message than 'Bad choice'.

from __future__ import print_function

IG = '''\
tiger
lion
elephant
deer
pigeon
fox
hyena
leopard
cheatah
hippo
'''

data = IG.splitlines()
for num, name in enumerate(data, 1):
    print('{0}: {1}'.format(num, name))

exitnum = num + 1
print('{0}: {1}'.format(exitnum, 'exit'))
while True:
    choice = raw_input('Enter your choice [1-{0}] : '.format(exitnum))
    try:
        choice = int(choice)
        if not 1 <= choice <= exitnum:
            raise ValueError
    except ValueError:
        print('Bad choice')
        continue
    if choice == exitnum:
        break
    elif choice == 1:
        print('Tigers are awesome')
    else:
        print('You chose {0}'.format(data[choice-1]))

print('Goodbye')

demo output

1: tiger
2: lion
3: elephant
4: deer
5: pigeon
6: fox
7: hyena
8: leopard
9: cheatah
10: hippo
11: exit
Enter your choice [1-11] : 3
You chose elephant
Enter your choice [1-11] : c
Bad choice
Enter your choice [1-11] : 1
Tigers are awesome
Enter your choice [1-11] : 12
Bad choice
Enter your choice [1-11] : 4
You chose deer
Enter your choice [1-11] : 11
Goodbye

Tested on Python 2.6.6. This code will also work correctly on Python 3, you just need to change raw_input to input for Python 3. But please don't use input on Python 2.