OpenRefine: 'Fill Up' replacing values along one column

Question

I have following table

╔════════╦════════╦════════╦════════╗
║ record ║ Brand  ║ Model  ║ Spec   ║
╠════════╬════════╬════════╬════════╣
║   1    ║   X    ║ null   ║ 1      ║
║        ║   X    ║ DF     ║ 3      ║
║        ║   X    ║ null   ║ 5      ║
║   2    ║   Y    ║ null   ║ 1      ║
║        ║   Y    ║ AB     ║ 3      ║
║        ║   Y    ║ null   ║ 5      ║
╚════════╩════════╩════════╩════════╝

And would like to get following

╔════════╦════════╦════════╦════════╗
║ record ║ Brand  ║ Model  ║ Spec   ║
╠════════╬════════╬════════╬════════╣
║   1    ║   X    ║ DF     ║ 1      ║
║        ║   X    ║ DF     ║ 3      ║
║        ║   X    ║ DF     ║ 5      ║
║   2    ║   Y    ║ AB     ║ 1      ║
║        ║   Y    ║ AB     ║ 3      ║
║        ║   Y    ║ AB     ║ 5      ║
╚════════╩════════╩════════╩════════╝

ie. I'm dreaming about something like 'fill up' analogue to the fill down tutorial

I haven't found a functionality which covers that out of the box. Do you have further information?

Answer 1

Could you try with this quick hack ?

(use Transform on your column "Model")

row.record.cells['Model'].value[0]

Here is the dataset I used

record,Brand,Model,Spec
1,X,,1
,X,DF,3
,X,,5
2,Y,,1
,Y,AB,3
,Y,,5

Demo