How do I add a Vectors.dense
column to a pyspark dataframe?
import pandas as pd
from pyspark import SparkContext
from pyspark.sql import SQLContext
from pyspark.ml.linalg import DenseVector
py_df = pd.DataFrame.from_dict({"time": [59., 115., 156., 421.], "event": [1, 1, 1, 0]})
sc = SparkContext(master="local")
sqlCtx = SQLContext(sc)
sdf = sqlCtx.createDataFrame(py_df)
sdf.withColumn("features", DenseVector(1))
Gives an error in file anaconda3/lib/python3.6/site-packages/pyspark/sql/dataframe.py
, line 1848:
AssertionError: col should be Column
It doesn't like the DenseVector
type as a column. Essentially, I have a pandas dataframe that I'd like to transform to a pyspark dataframe and add a column of the type Vectors.dense
. Is there another way of doing this?
Constant Vectors
cannot be added as literal. You have to use udf
:
from pyspark.sql.functions import udf
from pyspark.ml.linalg import VectorUDT
one = udf(lambda: DenseVector([1]), VectorUDT())
sdf.withColumn("features", one()).show()
But I am not sure why you need that at all. If you want to transform existing columns into Vectors
use appropriate pyspark.ml
tools, like VectorAssembler
- Encode and assemble multiple features in PySpark
from pyspark.ml.feature import VectorAssembler
VectorAssembler(inputCols=["time"], outputCol="features").transform(sdf)