UPDATE:
As of Xcode 9.3, which includes Swift 4.1, the array equality works as expected, and the code in the original question compiles without errors.
However, please see the accepted answer, because it provides a better, more modern solution.
The original question is below:
When I try to declare an instance of a generic enum with type [Post]
, I get an error saying
Type '[Post]' does not conform to protocol 'Equatable'
which is nonsense, because Post
conforms to Equatable
and I can actually compare two [Post]
instances with no compilation errors?
In the following example, I extend Post
and Result<T>
types with Equatable
and then I do a few tests:
Post
types: OK[Post]
types: OKResult<Post>
types: OKResult<[Post]>
types: ERRORimport Foundation
struct Post {
let text: String
}
extension Post: Equatable {}
func ==(lhs: Post, rhs: Post) -> Bool {
return lhs.text == rhs.text
}
enum Result<T: Equatable> {
case success(result: T)
case error
}
extension Result: Equatable {
static func ==(lhs: Result<T>, rhs: Result<T>) -> Bool {
switch (lhs, rhs) {
case let (.success(lhsVal), .success(rhsVal)):
return lhsVal == rhsVal
case (.error, .error):
return true
default:
return false
}
}
func test() {
// Test 1: Check Post type for equality: OK
let post1: Post = Post(text: "post 1")
let post2: Post = Post(text: "post 2")
if post1 == post2 {
print("equal posts")
}
// Test 2: Check [Post] type for equality: OK
let arrayOfPosts1: [Post] = [ post1, post2 ]
let arrayOfPosts2: [Post] = [ post1, post2 ]
if arrayOfPosts1 == arrayOfPosts2 {
print("equal arrays of post")
}
// Test 3: Check Result<Post> type for equality: OK
let result1: Result<Post> = Result<Post>.success(result: post1)
let result2: Result<Post> = Result<Post>.success(result: post2)
if result1 == result2 {
print("equal results of post")
}
// Test 4: Check Result<[Post]> type for equality: ERROR
// Compiler error: "Type '[Post]' does not conform to protocol 'Equatable'"
let arrayResult1: Result<[Post]> = Result<[Post]>.success(result: arrayOfPosts1)
let arrayResult2: Result<[Post]> = Result<[Post]>.success(result: arrayOfPosts2)
if arrayResult1 == arrayResult2 {
print("equal results of array of posts")
}
}
Swift 4.1 update:
With the introduction of conditional conformance in Swift 4.1, Array
now conforms to Equatable
, so the issue should be resolved without the need to resort to any workarounds.
Also, Swift now allows a type to automatically synthesize Equatable
conformance, provided all its members are Equatable
, simply by declaring Equatable
conformance as part of the original type definition (not an extension) but without implementing any of its requirements. This works for enums provided associated values, if any, are Equatable
.
The code from this question can now be written much more concisely as below:
import Foundation
struct Post: Equatable {
let text: String
}
enum Result<T>: Equatable where T: Equatable {
case success(result: T)
case error
}
This code will pass all the tests specified in the question:
func test() {
// Test 1: Check Post type for equality: OK
let post1 = Post(text: "post")
let post2 = Post(text: "post")
if post1 == post2 {
print("equal posts")
}
// Test 2: Check [Post] type for equality: OK
let arrayOfPosts1 = [post1, post2]
let arrayOfPosts2 = [post1, post2]
if arrayOfPosts1 == arrayOfPosts2 {
print("equal arrays of post")
}
// Test 3: Check Result<Post> type for equality: OK
let result1 = Result<Post>.success(result: post1)
let result2 = Result<Post>.success(result: post2)
if result1 == result2 {
print("equal results of post")
}
// Test 4: Check Result<[Post]> type for equality: OK
let arrayResult1: Result<[Post]> = Result<[Post]>.success(result: arrayOfPosts1)
let arrayResult2: Result<[Post]> = Result<[Post]>.success(result: arrayOfPosts2)
if arrayResult1 == arrayResult2 {
print("equal results of array of posts")
}
}
Here is the output:
test()
/*
prints:
equal posts
equal arrays of post
equal results of post
equal results of array of posts
*/