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wolfram-mathematicaderivativecalculus

How do I find the absolute minimum and maximum of a function on the giving interval using Wolfram Mathematica program?

I know how to find the derivatives however i don’t know how to use mathematica to find the absolute value. And compare with the graph and 2nd Derivatives? f(x) = 3x^(2/3) -2x +1 on [-1,8]

Solution

  • Is this what you're after?

    f[x_] := 3 x^(2/3) - 2 x + 1
max = First@FindMaximum[{f[x], -1 <= x <= 8}, x];
min = First@FindMinimum[{f[x], -1 <= x <= 8}, x];
Plot[{f[x], f''[x], max, min}, {x, -1, 8},
 PlotLegends -> "Expressions"]

    enter image description here