Parsing arguments as single line or using a specified delimiter in Python

Question

I want to parse the command line arguments while attempting to call the program in the following manner:

python plot.py --w --Develop origin plot --+3.5

I have been using sys.argv to parse them using a for loop:

for arg in sys,argv:
    print(arg)

Output:

plot.py
--w
--Developoriginplot
--+3.5

But I wish to get the output as follows:

plot.py
w
Develop origin plot
+3.5

Is there a way to split the line by specifying the delimeter -- ?

Answer 1

" ".join() the args first, then split by --.

import sys

args = " ".join(sys.argv) # join by spaces
args = [a.strip() for a in args.split("--")] # split by --, remove any extra spaces
print(args)
print("\n".join(args))

Output:

$ python plot.py --w --Develop origin plot --+3.5
['plot.py', 'w', 'Develop origin plot', '+3.5']
plot.py
w
Develop origin plot
+3.5