I am using the regular expression dEF\w+\(\w+\)=.*?;
in order to find patterns of the following form:
dEFPFC(pATREF)=dIDOSSEGPfc(pIDOSSeg);
dEFTur(pATREF)=dIDOSSEGTurnaround(pIDOSSeg);
The problem is that it also taking into account patterns that have ==
. I don't want that.
this pattern dEFOriDate(pNextEF)==dEFDesDate(pATREF));
should be ignored because it has ==
.
I tried using dEF\w+\(\w+\)={1}.*?;
but it didn't work
I tested the regular expression on https://regex101.com/.
Add a negative (?!=)
lookahead after =
:
dEF\w+\(\w+\)=(?!=).*?;
^^^^^
The (?!=)
lookahead will fail a match if the =
(matched with =
) is followed with another =
.
See the regex demo.