Newton's Method in C++

Question

I am trying to translate f(x) = x − e^-(x2) in c++ source code but I keep getting errors. I have tried :

double f(double x)
{
    exp = pow(-x, 2);
    double result = x - exp;
    return x;

};

Any insight? If it helps, I am using Code::Blocks

Answer 1

#include <math.h>
double f(double x)
{
    return x - exp(-(x*x));
}