I have a numpy array cols2:
print(type(cols2))
print(cols2.shape)
<class 'numpy.ndarray'>
(97, 2)
I was trying to get the first column of this 2d numpy array using the first code below, then i got a vector instead of my ideal one column of data. the second code seem to get me the ideal answer, but i am confused what does the second code is doing by adding a bracket outside the zero?
print(type(cols2[:,0]))
print(cols2[:,0].shape)
<class 'numpy.ndarray'>
(97,)
print(type(cols2[:,[0]]))
print(cols2[:,[0]].shape)
<class 'numpy.ndarray'>
(97, 1)
cols2[:, 0]
specifies that you want to slice out a 1D vector of length 97
from a 2D array. cols2[:, [0]]
specifies that you want to slice out a 2D sub-array of shape (97, 1)
from the 2D array. The square brackets []
make all the difference here.
v = np.arange(6).reshape(-1, 2)
v[:, 0]
array([0, 2, 4])
v[:, [0]]
array([[0],
[2],
[4]])
The fundamental difference is the extra dimension in the latter command (as you've noted). This is intended behaviour, as implemented in numpy.ndarray.__get/setitem__
and codified in the NumPy documentation.
You can also specify cols2[:,0:1]
to the same effect - a column sub-slice.
v[:, 0:1]
array([[0],
[2],
[4]])
For more information, look at the notes on Advanced Indexing in the NumPy docs.