DRF json 404 insetad of html page

Question

I would like to replace default django 404 (and other in the future) with the DRF response, as easy as it is possible, just to return (standard DRF response):

{
    "detail": "Not found."
}

So I put this code in my url.py file.

from rest_framework.exceptions import NotFound
from django.conf.urls import handler404
handler404 = NotFound

When I set Debug flag (in the set Ture I'm geting 500, when set it to False 404 but in the html form.

I've read doc here: http://www.django-rest-framework.org/api-guide/exceptions/ but to be honest I don't know how to put this into reality.

it seems to be easy, but somehow I failed to implement this (above code comes form the other SO threads).

Thank you in advance

Answer 1

You should create a custom view for the 404 then to use it. for example:

in views.py:

from django.http import HttpResponseNotFound
import json

def error404(request, exception):
    response_data = {}
    response_data['detail'] = 'Not found.'
    return HttpResponseNotFound(json.dumps(response_data), content_type="application/json")

then in urls.py:

from django.conf.urls import handler404

from yourapp.views import error404

handler404 = error404