I want that the parts that are "whited" to get the image blurred.
I've tried using pseudo elements ::after and ::before to add the overlays but could only blurred the overlay.
tried with borders 2nd example codepen, but no sucess because with the transparent it creates a "square".
https://codepen.io/giventofly/pen/RQpqYZ
.hero-image {
width: 1280px;
height: 800px;
background-image: linear-gradient(rgba(46, 51, 82, 0.6) 100%, transparent 0), linear-gradient(125deg, rgba(255, 255, 255, 0.5) 35%, transparent 0), linear-gradient(-55deg, rgba(255, 255, 255, 0.5) 25%, transparent 0),
url('https://cdn.vox-cdn.com/thumbor/NU6lcSN3DGmjF7NhZp6ixY3HxgQ=/0x0:1620x1080/1200x800/filters:focal(0x0:1620x1080)/cdn.vox-cdn.com/uploads/chorus_image/image/46510678/Tarmogoyf_DGM_1920x1080_Wallpaper.0.0.jpg');
background-size: cover;
background-repeat: no-repeat;
background-position: center;
z-index: 10;
}
<div class="hero-image"></div>
I only want to blur the part of the image that is "behind" the white linear-gradient
I'm sure someone can refine this approach a bit, but the main takeaways are:
clip-path
on the top image to display the non-blurred region..img-overlay {
display: inline-flex;
position: relative;
overflow: hidden;
}
.img-overlay::before {
content: '';
position: absolute;
top: 0;
right: 0;
bottom: 0;
left: 0;
background-color: rgba( 255, 255, 255, 0.5 );
z-index: 1;
}
.img-overlay img:first-child {
position: absolute;
top: 0;
left: 0;
filter: blur( 3px);
z-index: 0;
}
.img-overlay img:last-child {
position: relative;
z-index: 2;
-webkit-clip-path: polygon(25% 0%, 100% 0%, 75% 100%, 0% 100%);
clip-path: polygon(25% 0%, 100% 0%, 75% 100%, 0% 100%);
}
<div class="img-overlay">
<img src="http://unsplash.it/400/400?image=16">
<img src="http://unsplash.it/400/400?image=16">
</div>