Comparison operators Bash

Question

Is it possible to collect "True or False" from a comparison in bash? Without using "if".

Example ( let me make in another language )

x = 1
y = 1
z = x == y 
print(z) #Returns true

How is it in bash if is possible?

Solved

x=1
y=1
[[ $x -eq $y ]] && z=true || z=false
echo $z #Returns true

Thanks @Viktor & @randomir

Answer 1

You can just use test, without if:

x=1
y=1
[ $"{x}" -eq $"{y}" ] && echo "True" || echo "False"

Here, if x equal y, logical AND (&&) works, and script echo "True".

If x not equal, logical OR (||`) works, script echo "False".

Upd. by @randomir advice, another available solutions:

(( $"x" == $"y" )) && echo True || echo False

Or:

[[ $"a" == $"y" ]] && echo True || echo False