I am trying to use a clean arrow function that calls yield fork(....)
. I have a lot of places this happens. I am trying to do this:
const { ids } = yield take('REQUEST');
// ids is array of numbers [1, 2, 3]
ids.forEach(id => yield fork(requestWorker, id)); ////// this is what im trying to do - this is pseudo-code i know you cant use in non-generators (non-super-star functions)
However this does not work and i am having to do:
for (const id of ids) {
yield fork(requestWorker, id);
}
instead of the:
ids.forEach(id => yield fork(requestWorker, id)); // this is pseudo-code i know you cant use in non-generators (non-super-star functions)
Is there a cleaner way then a for-of loop? Like this arrow function method?
You could yield another generator
function* take(x) {
var id = /* ... */,
requesWroker = /* ... */;
yield* fork(requesWroker, id);
}
var all = [...take('REQUEST')];