python urllib2 document.login

Question

How would you go about logging into a website that is set up like so, using python urllib2

The below is the javascript handler on the form and a onsubmit. How would I process this in python?

<script>

function handleLogin() {document.login.un.value = document.login.username.value;document.login.width.value = screen.width;document.login.height.value = screen.height;}

</script>

Below is the html form with all the components to send as post. What holds me up is the onsubmit function.

<form id='login' name='login' method='post' onsubmit="handleLogin();" action='login.php'>

<input class="txtbox glow" type="text" id="username" name="username" value="blanksss">

<input class="txtbox glow" type="password" id="password" name="pw" size="18" autocomplete="off" onkeypress="checkCaps(event)">

<input class="checkbox" type="checkbox" id="rememberUn" name="rememberUn" checked="checked">

<input class="loginButton" type="submit" id="Login" name="Login" value="Login">

</form>

Python Code I have that works with easy sites without javascript is:

cj = cookielib.CookieJar()
opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj))
opener.addheaders.append(('User-agent', 'Mozilla/4.0'))
opener.addheaders.append( ('Referer', 'https://login.site.com/') )
login_data = urllib.urlencode({'username' : 'mylogin',
                               'pw' : 'mypass',
                               'Login' : 'Login',
                               'rememberUn' : 'checked'
                               })
resp = opener.open('https://login.site.com/', login_data)
website = opener.open('https://eu1.site.com/a03/o')

bowl = BeautifulSoup(website)

Any thoughts on how to process javascript code then post the finished results to the action of the form?

Thanks

Answer 1

use requests

import requests

data = {
      "username" : "youruser",
      "password" : "yourpass",
      "Login" : "Login",
}
r = requests.post(url, data=data)

this Script Will Work On Python 2.7