Python : Multiple Inheritance : Why is instance variable of super's super class is not accessible?

Question

This is the code I am trying to execute, in Line 1 originally it was super().super().__init__() which wasn't working (giving out error).

class A:
    def __init__(self):
        self.var1=5

class B(A):
    def __init__(self):
        self.var2=10

class C(B):
    def __init__(self):
        self.var3=20
        super().__init__() ## Line 1

c=C()
print(c.var1)

EDIT - When I tried printing the variable of class A using object of class B it works fine

class A:
    def __init__(self):
        self.var1=5

class B(A):
    def __init__(self):
        self.var2=10
        super().__init__()

b=B()
print(b.var1)

My question is why is c.var1 not giving out right output? (in both the cases, super().__init__() and super().super().__init__() and how can I access it?

Answer 1

Here is a little test for you that will help;

class A:
    def __init__(self):
        self.var1 = 5
        print("In A")

class B(A):
    def __init__(self):
        self.var2 = 10
        print("In B")

class C(B):
    def __init__(self):
        self.var3 = 20
        print("In C")
        super().__init__() ## Line 1

c = C()

will print;

In C
In B

but if you add a call in B to the constructor of A;

class A:
    def __init__(self):
        self.var1 = 5
        print("In A")

class B(A):
    def __init__(self):
        self.var2 = 10
        print("In B")
        super().__init__()

class C(B):
    def __init__(self):
        self.var3 = 20
        print("In C")
        super().__init__() ## Line 1

c = C()

You get what you would expect;

In C
In B
In A

and this...

print(c.var1)
5