Why is the line end character not included in the char*?

Question

Function TrimRight takes a line and removes all spaces at the end.

void TrimRight(char *s) // input "somestring   " (3 spaces at the end)
{
    // Here s == "somestring   \0" and strlen(s) == 14
    int last = strlen(s) - 2;
    std::cout << "Last1: " << s[last] << std::endl; // Last == ' '
    while (s[last] == ' ')
    {
        --last;
    }
    std::cout << "Last2: " << s[last] << std::endl;  // Last == 'g'
    s[last + 1] = '\0';
    // Here s == "somestring" and strlen(s) == 10
}

Questions is why s!= "somestring/0" after TrimRight(s)? I'm using MVS 2017. Thanks.

Answer 1

You thought after TrimRight(s), s become something\0.

But in TrimRight(s) function, while loop just passed from last index.

Pass mean it didn't delete whitespace and \0.

so s is not something\0. It is something\0 \0 because of "just pass".