How to simplify method using Option or PartialFunction

Question

I need some help to modify(simplify) my code.
Here an example:

def getBids(rawBids: RDD[List[String]], exchangeRates: Map[String, Double]): RDD[BidItem] = {
    rawBids.filter(bidList => !bidList(2).matches(ERROR_REGEXP))
      .flatMap(bidList => {
        Constants.TARGET_LOSAS.map { losa =>
          val indexOfLosa = Constants.BIDS_HEADER.indexOf(losa)
          if (bidList(indexOfLosa) != null && !bidList(indexOfLosa).equals("") && isDoubleNumber(bidList(indexOfLosa))) {
            BidItem(bidList.head, bidList(1), losa, bidList(indexOfLosa).toDouble)
          } else {
            BidItem(bidList.head, bidList(1), losa, 0)
          }
        }
      })
      .filter(unit => unit.price != 0)
      .map(unit => {
        val convertedPrice = usdToEur(unit.price, unit.bidDate, exchangeRates)
        val convertedDate = changeDateFormat(unit.bidDate)
        BidItem(unit.motelId, convertedDate, unit.loSa, convertedPrice)
      })
  }

I need to change flatMap method and avoid situation with "ELSE" part of code
As far as I know, we can use partial functions or [Option]. It can help us to avoid situation if our "if" statement is FALSE. If I remove ELSE part from code, scala don't give me a chance to compile my code. Thanks!

Answer 1

val doubleValue = Option(bidList(indexOfLosa))
  .filterNot(_.equals(""))
  .filter(isDoubleNumber)
  .map(_.toDouble)
  .getOrElse(0)
BidItem(bidList.head, bidList(1), losa, doubleValue)