RegEx: Remove pattern and everything after it

Question

I have strings with tags <p> and </p> I want to just get everything inbetween the tags but not the tags themselves.

I have gotten one half of the RegEx to work: ^[^_]*<p> This gives me the beginning but I still need another RegEx to get rid of </p>.

Answer 1

using lookbehind and lookahead to keep tags out of match and using /s modifier so that . matches also newlines

(?<=<p>).*?(?=</p>)

otherwise without /s modifier

(?<=<p>)[\s\S]*?(?=</p>)

because if perl can be shortended using \K, still to keep out of match

<p>\K.*?(?=</p>)