Search code examples
pythontkinterattributeerror

How to delete label generated from loop in tkinter?

So I'm trying to delete labels when a button is clicked, but I get an error on doing so.

This is a loop that generates labels based on the list that I have declared earlier.

    t = 150
    i = 0
    for p in products_list:
        self.pr1 = Label(self.right, text=str(products_list[i]), font=('arial 16 bold'), bg='steelblue', fg='white').place(x=0, y=t)
        self.pr2 = Label(self.right, text=(str(quantity_list[i])), font=('arial 16 bold'), bg='steelblue', fg='white').place(x=130, y=t)
        self.pr3 = Label(self.right, text=(str(price_list[i])), font=('arial 16 bold'), bg='steelblue', fg='white').place(x=240, y=t)
        t += 40
        i += 1

Now I'm trying to delete those labels when I click a button. I have created a print_bill function which has to delete the labels. I tried:

def print_bill(self):
    f = open(str(date), "w+")
    f.write("Bill Bill Bill")
    f.close()

    tkinter.messagebox.showinfo("Bill", "Bill Generated Successfully")
    self.pr1.destroy()
Solution

  • Your problem is this line:

    self.pr1 = Label(...).place(x=0, y=t)

    What you're basiclly doing in this line, is creating a Label object, calling .place on that object in-place, and then assigning the result of the method to self.pr1. Since Label.place returns, None, self.pr1 is assigned to None.

    You need to call the .place method on the label object, after assigning it to self.pr1. Otherwise, you loose all references to the Label object created and it's destroyed.

    self.pr1 = Label(...)
self.pr1.place(x=0, y=t)

    In other words, Label.place doesn't work in-place. After doing it's work, it returns no references to the object it was called on.