I am writing a very simple script that calls another script, and I need to propagate the parameters from my current script to the script I am executing.
For instance, my script name is foo.sh and calls bar.sh.
foo.sh:
bar $1 $2 $3 $4
How can I do this without explicitly specifying each parameter?
Use "$@" instead of plain $@ if you actually wish your parameters to be passed the same.
Observe:
$ cat no_quotes.sh
#!/bin/bash
echo_args.sh $@
$ cat quotes.sh
#!/bin/bash
echo_args.sh "$@"
$ cat echo_args.sh
#!/bin/bash
echo Received: $1
echo Received: $2
echo Received: $3
echo Received: $4
$ ./no_quotes.sh first second
Received: first
Received: second
Received:
Received:
$ ./no_quotes.sh "one quoted arg"
Received: one
Received: quoted
Received: arg
Received:
$ ./quotes.sh first second
Received: first
Received: second
Received:
Received:
$ ./quotes.sh "one quoted arg"
Received: one quoted arg
Received:
Received:
Received: