I want to use Spark REST API to get metrics and publish to cloud watch. But the RESR API is like :
val url = "http://<host>:4040/api/v1/applications/<app-name>/stages"
If I give the master host and app id it works but how can I use this in a job and figure our master host and app-name dynamically ? Is there any way to get those information ?
Using Spark 2.1
Tried :
import org.apache.spark.sql.SparkSession
val id = spark.sparkContext.applicationId val url = spark.sparkContext.uiWebUrl.get
case class SparkStage(name: String, shuffleWriteBytes: Long, memoryBytesSpilled: Long, diskBytesSpilled: Long)
val path = url + "/api/v1/applications/" + id + "/stages"
implicit val formats = DefaultFormats
val json = fromURL(path).mkString
val stages: List[SparkStage] = parse(json).extract[List[SparkStage]]
I am getting :
java.io.IOException: Server returned HTTP response code: 500 for URL: http://112.21.2.151:4040/api/v1/applications/application_1515337161733_0001
at sun.net.www.protocol.http.HttpURLConnection.getInputStream0(HttpURLConnection.java:1876)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1474)
at java.net.URL.openStream(URL.java:1045)
at scala.io.Source$.fromURL(Source.scala:141)
at scala.io.Source$.fromURL(Source.scala:131)
... 64 elided
If you know the host you can query applications
endpoint:
http://localhost:4040/api/v1/applications
and parse the result to get applicaiton id.
To get applicationId
and host
from the application use respective SparkContext
methods:
val spark: SparkSession
spark.sparkContext.applicationId
spark.sparkContext.uiWebUrl