select pl.label_id,
( select pv.label_value
from PV_I18N_ACTIVE_LOCALE_LABEL pv
where pv.locale_id='English'
and pv.label_type_id = 'LABEL'
and pv.label_id = pl.label_id ) as 'English',
( select pv.label_value
from PV_I18N_ACTIVE_LOCALE_LABEL pv
where pv.locale_id='Hindi'
and pv.label_type_id = 'LABEL'
and pv.label_id = pl.label_id ) as 'Hindi',
from PV_I18N_ACTIVE_LOCALE_LABEL pl
where pl.label_type_id = 'LABEL'
order by pl.label_id
The error is
ORA-00923: FROM keyword not found where expected
You have extra ,
in your SQL
, which is just before FROM
keyword.
and pv.label_id = pl.label_id ) as 'Hindi',
from PV_I18N_ACTIVE_LOCALE_LABEL pl
==Edited==
I'm not sure, why are you making query so complex, when it can be done easily. Why are you using inline query, when same thing you can achieve by using CASE
statement.
select CASE WHEN pl.locale_id='English' THEN
pl.label_value
END as 'English',
CASE WHEN pl.locale_id='Hindi' THEN
pl.label_value
END as 'Hindi' from PV_I18N_ACTIVE_LOCALE_LABEL pl where pl.label_type_id = 'LABEL';