I have a string which contains following text.
\xD0\xA4\xD0\xB5\xD0\xB4\xD0\xBE\xD1\x80\xD0\xBE\xD0\xB2
It is not a literal. In string it's stored as separate characters like this ['\','x','D','0','\','x','A','4',...]
How to convert this string to normal characters?
Go accepts hexadecimal rune literals.
So you can use your input as a regular string:
fmt.Println("\xD0\xA4\xD0\xB5\xD0\xB4\xD0\xBE\xD1\x80\xD0\xBE\xD0\xB2")
Федоров
Playground example.
If you start with the actual string ["\" "x" "D" "0" ...]
, you'll need to convert the individual 4-byte sequences to characters.
One dirty way is:
s := `\xD0\xA4\xD0\xB5\xD0\xB4\xD0\xBE\xD1\x80\xD0\xBE\xD0\xB2`
s2, _ := hex.DecodeString(strings.Replace(s, "\\x", "", -1))
fmt.Printf("%s", s2)
Playground example.
Edited to answer edited question.