Extract part of file name using KornShell

Question

I have a file name, for example: xxdatafile_20110120123030_12342.dat. I want to extract "XXdatafile_" from the file name.

How do I do that using Ksh on Unix?

Answer 1

$ file=xxdatafile_20110120123030_12342.dat
$ echo ${file%%_*}
xxdatafile