I'm trying to trigger backtracking on a goal but in a dynamic way, if it's possible. To better exemplify my issue let's say we have the following PROLOG code:
num(1).
num(2).
num(3).
num(4).
num(5).
Then I head to SWI-Prolog and call: num(X)
. This triggers backtracking looking for all solutions, by typing ;
.
What I would like is to remove those facts (num(1)
,num(2)
, etc) and replace that code with something thata generates those facts dynamically. Is there any way in which I can achieve this? Someting of the sorts,maybe?
num(X):- for X in 1..5
that yields the same solutions as the code above?
As far as I know, the findall
predicate returns a list, which is not what I'm looking for. I would like to backtrack through all answers and look through them using ;
in the console.
Yes there is, and you were already very close!
:- use_module(library(clpfd)).
num(X) :-
X in 1..5.
?- num(X).
X in 1..5.
?- num(X), X #>3.
X in 4..5.
?- num(X), labeling([], [X]).
X = 1
; X = 2
; X = 3
; X = 4
; X = 5.