gremlin> a = graph.addVertex("name", "alice")
gremlin> b = graph.addVertex("name", "bobby")
gremlin> c = graph.addVertex("name", "cindy")
gremlin> d = graph.addVertex("name", "david")
gremlin> e = graph.addVertex("name", "eliza")
gremlin> a.addEdge("rates",b,"tag","ruby","value",9)
gremlin> b.addEdge("rates",c,"tag","ruby","value",8)
gremlin> c.addEdge("rates",d,"tag","ruby","value",7)
gremlin> d.addEdge("rates",e,"tag","ruby","value",6)
gremlin> e.addEdge("rates",a,"tag","java","value",9)
g.V().has('name', 'alice').repeat(out()).times(6).cyclicPath().path().by('name')
I want to end with alice node. and I want to repeat all the step not want to specify time as 6. The requirement is I want to get all the loop from alice or get all the loops from the graph.
You can refer to the Cycle Detection section in the TinkerPop Recipes - it adapts fairly easily to your sample graph:
gremlin> g.V().has('name', 'alice').as('a').
......1> repeat(out().simplePath()).
......2> emit(loops().is(gt(1))).
......3> both().where(eq('a')).
......4> path().
......5> by('name').
......6> dedup().
......7> by(unfold().order().dedup().fold())
==>[alice,bobby,cindy,david,eliza,alice]