Private non-virtual Base class function is called instead of the one in Derived class

Question

class Base{
public:
    void callF(){ F(); }
private:
    void F(){}
};
class Derived: public Base{
public:
    void F(){}
};
int main(){
    Derived d;
    d.callF();
}

Surprisingly for me,the Base F() is called. I don't understand why. F() was declared and defined in Base class as private,so the Derived object doesn't even know about the existence of such a function in Base. Derived class has its own F(), yet that function is ignored. The question is "Why is the Base class F() called? ".

Answer 1

It goes like this.

1. The Base::callF function is called. It is public so there's no problem in calling it forom main.
2. The Base::callF function wants to call a function named F. The only F visible to Base::callF is Base::F. It is private, but callF is a member of Base so it gets to see and use all other members, including the private ones.
3. The Derived::F function has nothing to do with any of this. It's just another function, unrelated to Base::F, which happens to have a similar name.