I have a for loop from range 0 to 1000 in which i want get all possible combinations of how the current number can be split up into for example 4 numbers and also use xor
on these combinations :
split_up_in = 4
for i in range(0, 1000):
combinations = getAllCombinationsXORs(i, split_up_in)
print(combinations)
Update
Example:
i = 6
Split up into 4 numbers (only positive numbers without zero)
1 1 2 2
xor: 0 or 1 1 1 3
xor: 2 and so on filling in all the possibilities to sum up to the number i = 6
The order is not important. 1 1 2 2
is the same as 1 2 1 2
Is there any faster way to do it in python
?
Maybe an in-built function.
Partitioning a number n into k parts must have a complexity of O(n^(k-1)), since the number of partitions itself is proportional to that. Therefore there is no faster algorithm for this problem.
If you want to print the results from 0 to 1000, then you should store the partitions and reuse them. Note that you only need to store the last k results because the recurrence relation has an order of k.