I have a string like:
<number>xx<->a<T>b<F>c<F>d<F>e<F>f<F>g<T>h<F>i<F>
How can I efficiently parse this string so that i.e.
xx
has a value of null
a
has a value of 1
b
has a value of
0
You can parse that with Regular Expressions. We first remove the initial <word>
at the start of the string, if it exists, and then look for pairs of word<word>
, saving them into key,value pairs in a dictionary using the codes
dictionary to convert _
, F
, T
, to null
, 0
, 1
.
import re
s = '<number>xx<->a<T>b<F>c<F>d<F>e<F>f<F>g<T>h<F>i<F>'
m = re.match(r'<(\w*?)>', s)
if m:
head = m.group(1)
s = s[m.end():]
print(head)
else:
print('No head group')
codes = {'-': 'null', 'F': '0', 'T': '1'}
pat = re.compile(r'(\w*?)<([-\w]*?)>')
out = {k: codes[v] for k, v in pat.findall(s)}
print(out)
output
number
{'xx': 'null', 'a': '1', 'b': '0', 'c': '0', 'd': '0', 'e': '0', 'f': '0', 'g': '1', 'h': '0', 'i': '0'}