i hope someone can help me, ive been struggling on this for 3 days now.
here is my situation, i am making a website with php, and i have 2 computers as servers with wampserver...
main server is 192.168.0.10
secondary server is 192.168.0.12
and a virtual machine where im trying out if the remote conection works
my website is hosted on my main server so the conexion query is...
$conexion = mysqli_connect("localhost","root","","dbdaq");
it works fine, i even have master to master replication on the servers.
but what i need to do is that when main server is down it needs to try to conect to the database on the seondary database, so im trying to use the code...
$conexion = mysqli_connect("localhost","root","","dbdaq");
if (!$conexion){
$conexion = mysqli_connect("192.168.0.12","root","password","dbdaq");
}
but when i manually turn of the mysql services on main server it doesnt actually try to use the other servers database...
it keeps giving me the error that says
Warning: mysqli_connect(): (HY000/2002): No connection could be made because the target machine actively refused it. in C:\wamp64\www\PaginaV2\Pagina\PHP y JS\Procesoalumno.php on line 2
Try this: use php's @
operator (the error control operator) to suppress the error message from the first connection failure. Try this.
$conexion = @mysqli_connect("localhost","root","","dbdaq");
if ( !$conexion ) {
$conexion = mysqli_connect("192.168.0.12","root","password","dbdaq");
}
It seems likely your code for the failover connection works correctly, but you still get an obnoxious error message. The @
operator suppresses the message.