How to handle error when duplicate entries are inserted into table? I tried the following and it is not working.
function leaveBalanceRecord($f3)
{
$sql =
"
INSERT
INTO users_leave_balance (user_id, period, leave_type, leave_balance, rollable_till_date)
VALUES (134, '2017-01', 1, 10.00, NULL)";
$results = $this->db->exec($sql);
if(!$results)
{
return 'Duplicate Entries';
}
return $results;
}
How to handle the error and update the record instead in case this error arises? Any help is appreciated. Thanks.
I see two solutions for your case:
1) Take benefit of the MySQL REPLACE INTO
syntax:
$sql='REPLACE INTO users_leave_balance etc.';
$this->db->exec($sql);
From the docs:
REPLACE works exactly like INSERT, except that if an old row in the table has the same value as a new row for a PRIMARY KEY or a UNIQUE index, the old row is deleted before the new row is inserted.
2) Catch the PDO exception:
$sql='INSERT INTO users_leave_balance etc.';
try {
$this->db->exec($sql);
} catch (\PDOException $e) {
$err=$e->errorInfo;
if ($err[0]==23000) {
// duplicate key: do something
} else {
// any other error
}
}
See this answer for details on how to enable PDO exceptions.