I need to test the number of entry of a specific lexicon (range index). I can do it using fn:count(cts:element-values()), but this will end up running too slowly with a large lexicon. Is there a better way to compute the total number of values ?
Note that I don't wan't the number of fragment as returned by cts:count-aggregate, but the number of values.
Thanks for help
No. There is no better query. Maybe run once and cache the results for reuse.
You don’t say how slow it is. It shouldn’t take more than a few seconds usually if you’ve got the right cluster size.