Switching between windows. Qt Widgets ( 1 widget in memory )

Question

For example I have 2 widgets and I press button on first widget. I need to delete first widget and create new widget. How is it possible? I mean some structure for this. I used stackedwidgets, but pages from stackedwidgets located in memory. I need to avoid this.

void Window::on_registrationButton_clicked(){
    ui->logWindow->hide();
    ui->RegistrWindow->show();
}

Answer 1

As you are going to eliminate the object you can not do it within the same class the object belongs to, you have to do it outside of it, for example in the following code I created a signal that is triggered when the button is pressed, this I have connected it to a lambda function where the new object is created and the object that emits it is eliminated.

class LogWindow: public QWidget{
    Q_OBJECT
public:
    LogWindow(const QString &text, QWidget *parent=Q_NULLPTR):QWidget(parent){
        setLayout(new QVBoxLayout);
        btn = new QPushButton(text, this);
        layout()->addWidget(btn);
        connect(btn, &QPushButton::clicked, this, &LogWindow::customSignal);
    }
signals:
    void customSignal();
private:
    QPushButton *btn;
};

class RegWindow : public QWidget{
    [...]
};

int main(int argc, char *argv[])
{
    QApplication a(argc, argv);
    LogWindow *log= new LogWindow("LogWindow");
    RegWindow *reg;
    QObject::connect(log, &LogWindow::customSignal, [&reg, &log](){
        reg = new RegWindow("RegWindow");
        reg->show();
        log->deleteLater();
    });
    log->show();
    return a.exec();
}

#include "main.moc"

The complete example can be found in the following link