Return specific value when list is out of range in Python

Question

How can I return a specific value if the list is out of range? This is the code I have so far:

def word(num):
  return ['Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday'][num-1]

word(1) will return 'Sunday', but how can I return a default value if num is not an integer between 1-7?

Thus, word(10) would return something like "Error".

Answer 1

Normal if/else should suffice.

def word(num):
    l = ['Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday']
    return l[num-1] if 0<num<=len(l) else "Error"

#driver code

>>> word(7)
=> 'Saturday'

>>> word(8)
=> 'Error'

>>> word(-10)
=> 'Error'