I have this directory.
.
├── animation
│ ├── animation-events
│ │ ├── app.js
│ │ ├── app.mustache.json
│ │ ├── create_view.sh
│ │ └── assets
│ │ └── dummy_character_sprite.png
│ └── change-frame
│ ├── app.js
│ ├── app.mustache.json
│ ├── create_view.sh
│ └── assets
│ └── dummy_character_sprite.png
├── app.css
├── app.mustache
├── bunch_of_functions.js
├── decorators.js
├── create_all_views.sh
└── displaying-a-static-image
├── app.js
├── app.mustache.json
├── create_view.sh
└── assets
└── piplup.png
I want for create_all_views.sh
to execute all create_view.sh
in the children directory. How can I achieve such thing?
As you are in Ubuntu, you have the GNU implementation of find
,
which has the -execdir
option,
and you can do like this:
find path/to/dir -name create_view.sh -execdir ./create_view.sh \;
That is,
for each create_view.sh
file it finds in the directory tree,
it will execute ./create_view.sh
in the directory of that file.