caesar python 3 syntax-error when converting string parts to ascii code, calculate the new character and convert it back to encrypted text

Question

I'm learning python3 on school after having had the basics of C programming. But now i've goten stuck on caesar form cs50. Though without use of the cs50 libraries.

So i've done the following:

Code:

print('ciphertext: ')

key = sys.argv[1]

for i in range(len(plain[i])

    if ord(plain[i]) > 64 and ord(plain[i]) < 91 or ord(plain[i]) > 96 and 
    ord(plain[i]) < 123

        ciphertext = chr(ord (plain[i]) + key %26)

print('ciphertext: {}'.format(ciphertext))

I get a syntax code on line 6 where ciphertext turned blue. Could someone tell me what i do wrong when i want to get the encrypted text out of this. Above this code i've defined plain.

Answer 1

There are a couple dozen syntax errors in your code Here fixed it for you try reviewing it

import sys
print('ciphertext: ')

key = sys.argv[1]

for i in range(len(plain[i])):
if ord(plain[i]) > 64 and ord(plain[i]) < 91 and ord(plain[i]) > 96 and ord(plain[i]) < 123:

        ciphertext = chr(ord (plain[i]) + key %26)

print('ciphertext: {}'.format(ciphertext))