I have a rather simple question for you guys. In Java 8 it was introduced the Optional
type. I have two objects of type Optional<String>
and I want to know which is the more elegant way to concatenate them.
Optional<String> first = Optional.ofNullable(/* Some string */);
Optional<String> second = Optional.ofNullable(/* Some other string */);
Optional<String> result = /* Some fancy function that concats first and second */;
In detail, if one of the two original Optional<String>
objects was equal to Optional.empty()
, I want the whole concatenation to be empty too.
Please, note that I am not asking how to concatenate the evaluation of two Optional
s in Java, but how to concatenate two String
s that are inside some Optional
.
Thanks in advance.
The solution I found is the following:
first.flatMap(s -> second.map(s1 -> s + s1));
which can be cleaned using a dedicated method, such the following:
first.flatMap(this::concat);
Optional<String> concat(String s) {
second.map(s1 -> s + s1);
}
However, I think that something better can be found.
If we want to generalize to a list or an array of Optional<String>
, then we can use something similar to the following.
Optional<String> result =
Stream.of(Optional.of("value1"), Optional.<String>empty())
.reduce(Optional.of(""), this::concat);
// Where the following method id used
Optional<String> concat(Optional<String> first, Optional<String> second) {
return first.flatMap(s -> second.map(s1 -> s + s1));
}
Note that in order to compile the above code, we have to manually bind the type variable of Optional.empty()
to String
.