This is an example of the string that's being worked with:
xxxxxx[xxxxxx][7][xxxxxx][9][xxxxxx]
I'm having a little trouble matching the second occurrence of a match, I want to return the 2nd square brackets with a number inside. I have some regex finding the first square backets with numbers in a string:
\[+[0-9]+\]
This returns [7], however I want to return [9].
I'm using Javascript's replace function, the following regex matches the second occurrence (the [9]) in regex testeing apps, however it isn't replaced correctly in the Javascript replace function:
(?:.*?(\[+[0-9]+\])){2}
My question is how do I use the above regex to replace the [9] in Javasctipt or is there another regex that matches the second occurrence of a number in square brackets.
Cheers!
If xxx is just any string, and not necessarily a number, then this might be what you want:
(\[[0-9]+\]\[.*?\])\[([0-9]+)\]
This looks for the second number in []. Replace it with $1[<replacement>]. Play with it on rubular.
Your regular expression fails to work as intended because groups followed by + only end up holding the last [xxx].