I used the Python library OSMNx to draw an optimal route between several steps of a city trip. The final variable is a list of OSM ids.
Now, I'm trying to save this route as a shp or json files. The problem is that I need for that the latitude/longitude of each node, but I didn't found an OSMNx function to do that.
I tried get_route_edge_attributes (but coordinates are not a valid attribute for this function). Is there any way to get coordinates of an OSM node with this single id ?
you have all the attribute of each node and edge in the Graph. you can get node attributes using:
G.node[38862848]
#out: {'highway': nan,
# 'lat': 45.3210533,
# 'lon': -122.9790558,
# 'osmid': '38862848',
# 'ref': nan,
# 'x': 501641.47862882155,
# 'y': 5018616.5723966481}
G.node[38862848]['lat']
# out: 45.3210533
and to get edge attributes you can use G[u][v]:
G[5035130880][4963510289]
# out:
#{0: {'bridge': 'yes',
# 'geometry': <shapely.geometry.linestring.LineString at 0x7f90ad7d5860>,
# 'highway': 'secondary',
# 'length': 671.332597496,
# 'name': 'Northwest 185th Avenue',
# 'oneway': False,
# 'osmid': [124454683, 24446714, 124454682]}}
All attributes are also in GeoDataFrame's of the graph. If you have list of nodes, the easiest way to get the geometry of all nodes is:
import osmnx as ox
import networkx as nx
gdf_nodes, gdf_edges = ox.graph_to_gdfs()
path = nx.shortest_path(G, G.nodes()[0], G.nodes()[1])
gdf_nodes.loc[path]
#out:
# highway lat lon osmid ref x y geometry traffic_signals
#5035130880 NaN 45.5637 -122.868 5035130880 NaN 510334 5.04558e+06 POINT (510334.0390091945 5045583.999886028) 0
#4963510289 NaN 45.5698 -122.868 4963510289 NaN 510329 5.04625e+06 POINT (510329.3114555664 5046254.728223645) 0
# ...
the output is a GeoDataFrame.