There is an array of integers. There are also disjoint sets, A and B, each containing integers. You like all the integers in set A and dislike all the integers in set B. Your initial happiness is 0. For each integer in the array, if i in A, you add 1 to your happiness. If i in B, you add -1 to your happiness. Otherwise, your happiness does not change. Output your final happiness at the end.
Input Format
The first line contains integers n and m separated by a space. The second line contains n integers, the elements of the array. The third and fourth lines contain m integers, A and B respectively.
Output Format
Output a single integer, your total happiness.
Sample Input
3 2
1 5 3
3 1
5 7
Sample Output
1
Can someone please explain what is wrong with this solution? It passes some test, but fails on others.
input()
array = set(input().split())
set1 = set(input().split())
set2 = set(input().split())
res = len(set1 & array) - len(set2 & array)
print(res)
The problem is that you're transforming your inputs to sets, which in turn removes the duplicates. If you have repeated values in your input, with the set you're only adding/substracting 1 to the resulting happiness. If that's correct, your code is fine. If not, then you should work with lists rather than sets.
The code could be something like this:
# The first part should stay the same, without the set() call on array
input()
array = input().split()
list1 = set(input().split())
list2 = set(input().split())
# Now we use some list comprehension to get the happiness result
res = sum([1 for elem in array if elem in list1]) - sum([1 for elem in array if elem in list2])
The first sum accumulates the positive points, and the second one the negatives. It works with multiple occurences, adding/substracting one point per each.
EDIT
A more clear approach, to understand the for loop
# The first part should stay the same, without the set() call on array
input()
array = input().split()
list1 = set(input().split())
list2 = set(input().split())
# We create a variable res which will store the resulting happiness, initially 0
res = 0
# Now we iterate through the elements in array and check wheter they should add or substract
for elem in array:
# If the element is in list1, we add 1 to res
if elem in list1:
res += 1
# If the element is in list2, we substract 1 from res
elif elem in list2:
res -= 1