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Python dateformat does not match Portugese format locale

I'm trying to parse Portugese date into datetime. Below is what I'm trying:

import locale
from datetime import datetime
locale.setlocale(locale.LC_ALL, 'pt_PT.iso88591')
date_format = '%A, %d %B %Y, %H:%M'
date_str = 'sexta-feira, 8 de setembro de 2017, 20:08'
datetime.strptime(date_str, date_format)
Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "/usr/lib/python2.7/_strptime.py", line 332, in _strptime
    (data_string, format))
ValueError: time data 'sexta-feira, 8 de setembro de 2017, 20:08' does not 
  match format '%A, %d %B %Y, %H:%M'

Also tried below date_str but still getting the same error:

date_str = 'sexta-feira, 8 setembro 2017, 20:08'

What am I doing wrong here?

Solution

  • POSIX date and time format has limited support for different date formats. I suggest you take a look at PyICU:

    from datetime import datetime
from icu import Locale, DateFormat, ICUtzinfo, TimeZone
locale = Locale('pt_PT')
tz = ICUtzinfo.getInstance('Portugal')
now = datetime.now(tz)
df = DateFormat.createDateTimeInstance(DateFormat.kFull, DateFormat.kFull, locale)
s = df.format(now)
print s
now2 = df.parse(s)
print now2
s2 = df.format(now2)
print s2

    Output:

    sexta-feira, 8 de setembro de 2017 às 23:26:20 Hora de verão da Europa Central
1504905980.0
sexta-feira, 8 de setembro de 2017 às 23:26:20 Hora de verão da Europa Central

    I'm scraping a website so I need to convert a date string (sexta-feira, 8 de setembro de 2017, 20:08) into datetime so I can save it into database. How would I do that using PyICU?

    This would require custom CLDR pattern: 

    df = SimpleDateFormat("EEEE, d 'de' MMMM 'de' yyy, HH:mm", locale)
print df.parse('sexta-feira, 8 de setembro de 2017, 20:08')