In my folder, I want to delete the files that ends with 2 digits (10, 11, 12, etc.)
What I've tried is
rm [0-9]*
but it seems like it doesn't work.
What is the right syntax of doing this?
Converting comments into an answer.
Your requirement is a bit ambiguous. However, you can use:
rm -i *[0-9][0-9]
as long as you don't mind files ending with three digits being removed. If you do mind the three-digit files being removed, use:
rm -i *[!0-9][0-9][0-9]
(assuming Bash history expansion doesn't get in the way). Note that if you have file names consisting of just 2 digits, those will not be removed; that would require:
rm -i [0-9][0-9]
The -i option is for interactive. It is generally a bad idea to experiment with globbing and rm commands because you can do a lot of damage if you get it wrong. However, you can use other techniques to neutralize the danger, such as:
echo *[!0-9][0-9]
which echoes all the file names, or:
printf '%s\n' *[!0-9][0-9]
which lists the file names one per line. Basically, be cautious when experimenting with file deletion — don't risk making a mistake unless you know you have good backups readily available. Even then, it is better not to need to use them
See also the GNU Bash manual on:
^ in place of !.shopt built-in