loop - calling a series of indexed data

Question

I'm trying to generate a list of std_error by calling all the std_dev_of_sample_means by its [i] index and dividing that by its respective [i^.5], but I'm not sure how to properly call the [i] in the std_dev_of_sample_means. thanks!

sample_sizes2 = np.arange(1,1001,100)

mean_of_sample_means = []
std_dev_of_sample_means = []
for i in sample_sizes2:
    probabilities=make_throws(200,i)
    mean_of_sample_means.append(np.mean(probabilities))
    std_dev_of_sample_means.append(np.std(probabilities))
    std_error = std_dev_of_sample_means[i]/(i^.5)

print(std_dev_of_sample_means)
print(std_error)

Answer 1

I hope this is what you are looking for :) Do let me know if i misinterpreted your question

sample_sizes2 = np.arange(1,1001,100)

mean_of_sample_means = []
std_dev_of_sample_means = []
std_errors = []
for i in sample_sizes2:
    probabilities=make_throws(200,i)
    mean_of_sample_means.append(np.mean(probabilities))
    std_dev_of_sample_means.append(np.std(probabilities))
    std_errors.append(std_dev_of_sample_means[-1]/(i**.5)) # previously it was i^.5

print(std_dev_of_sample_means)
print(std_errors)

std_dev_of_sample_means[-1] refers to the value of the last element in the list (because the [-1] access the last value in the list). In this case it is the value that you just appended to std_dev_of_sample_means

Edit 1: changed i^.5 to i**.5. You were using ^ when you want a ** to raise a value to a power. Python interprets this as an xor.