I'm trying to solve the following exercise:
Reverse an array without using the reverse method, without using a second array, and without duplicating any of the values.
I've thought about making the array an object and then updating the array from the end to the beginning but I figured you can just update it as well.
Tried something simple like:
function reverseArray(array) {
for (var i = 0; i < array.length; i++) {
// var elem = array.shift();
var elem = array.shift()
array.push(elem)
}
return array
}
array = ['a', 'b','c','d','e'];
reverseArray(array);
But that doesn't really change it. Any advice or explanation on how to do this?
With ES6 syntax you don't need to copy a value into a temporary variable (is that what the last requirement is about?).
function reverse(arr) {
for(let i = 0, j = arr.length-1; i < j; i++, j--)
[arr[i], arr[j]] = [arr[j], arr[i]];
}
const arr = ['a','b','c','d','e'];
reverse(arr);
console.log(arr);
One may argue that arrays are created here (if engines don't optimise this away), just like splice
also creates an array (as its return value).