This is what I came on. Supposedly, the list[[ ]] would mean all the data.frames from the list, which it did not work.
list <- as.Date(list[[]][,2])
Not working, tried something as this
list <- lapply(list[,2], as.Date)
Again an error.
So, that being said, and shown, how can explicit in R languages, that I want to apply the function in all the elements of a column, for all the data.frames of the list, in the best way
I don't know how to do want you want with any of the apply
functions but a simple loop works
data1 = data.frame(y = seq(1,10),x=seq(from = 1789,to = 2789,length.out=10))
data2 = data.frame(y = seq(11,20),x=seq(from = 1789,to = 2789,length.out=10))
test = list(data1,data2)
for(i in 1:length(test)){
test[[i]][,2] = as.Date(test[[i]][,2],origin = "1899-12-30")
}
In this case I want to convert numeric excel dates in dates in R.
I tried modifying your second option to:
lapply(test,function(x) as.Date(x[,2],origin = "1899-12-30"))
but you would end up only with dates