How to split a Swiss address into a street and a zip code in Python?

I am looking for a solution to split a representative Swiss address into a street (and street number) and a zip code (and name of place).

Suggest, I have the following address:

'Bahnhofstrasse 1, 8001 Zürich'

The result I am looking for is:

street: 'Bahnhofstrasse 1'
place: '8001 Zürich'

However, sometimes there is a comma and sometimes not. But the postal code always consists of 4 digits?

I used the .split(') so far but that only works when a comma is present.

Solution

I don't expect city names to have digits in them, Use this Pattern ^(.*?),?\s*(\d{4}\D+)$ Demo

^               # Start of string/line
(               # Capturing Group (1)
  .             # Any character except line break
  *?            # (zero or more)(lazy)
)               # End of Capturing Group (1)
,               # ","
?               # (zero or one)(greedy)
\s              # <whitespace character>
*               # (zero or more)(greedy)
(               # Capturing Group (2)
  \d            # <digit 0-9>
  {4}           # (repeated {4} times)
  \D            # <character that is not a digit>
  +             # (one or more)(greedy)
)               # End of Capturing Group (2)
$               # End of string/line