Why can't a struct defined inside a function be used as functor to std::for_each?

Question

The following code won't compile. The compiler complains about *no matching function for call to for_each*. Why is this so?

#include <map>
#include <algorithm>

struct Element
{
    void flip() {}
};

void flip_all(std::map<Element*, Element*> input)
{
    struct FlipFunctor
    {
        void operator() (std::pair<Element* const, Element*>& item)
        {
            item.second->flip();
        }
    };

    std::for_each(input.begin(), input.end(), FlipFunctor());
}

When I move struct FlipFunctor before function flip_all, the code compiles.

Full error message:

no matching function for call to ‘for_each(std::_Rb_tree_iterator<std::pair<Element* const, Element*> >, std::_Rb_tree_iterator<std::pair<Element* const, Element*> >, flip_all(std::map<Element*, Element*, std::less<Element*>, std::allocator<std::pair<Element* const, Element*> > >)::FlipFunctor)’

Answer 1

std::for_each is a function template; one of the template parameters is the type of the function argument.

You cannot use a local type as a template argument. It's just a restriction currently in the language. In the forthcoming revision of C++, C++0x, this restriction is removed, so you can use local types as template arguments.

Visual C++ 2010 already supports the use of local classes as template arguments; support in other compilers may vary. I'd guess that any compiler that supports C++0x lambdas would also support the use of local classes as template arguments (this may not be entirely true, but it would make sense).