I have an Angular 4 application and my private.component.html
something like this:
<app-breadcrumb></app-breadcrumb>
<router-outlet></router-outlet>
And my routing:
const privateRoutes: Routes = [
{
path: '',
component: PrivateComponent,
children: [
{
path: 'dashboard',
component: DashboardComponent
},
{
path: 'settings',
component: SettingsComponent
},
{
path: 'companies',
component: CompaniesComponent,
children: [
{
path: 'add',
component: FormCompanyComponent
},
{
path: ':id',
component: CompanyComponent
}
]
}
]
}
];
All components on first level is rendered in router-outlet of PrivateComponent
. But I want (if possible) all other child (and I can have multiple levels), like /companies/add
or /companies/20
still rendered in the same router-outlet of my private template. My actual code, sure, expect I have the outlet inside the companies.component.html
.
This is important to implement my breadcrumb component and write "Home > Companies > Apple Inc.", for example.
It's possible create some structure like that?
Adding to @Karsten's answer, basically what you want is to have a componentless route and the empty path as the default component such as this:
const privateRoutes: Routes = [
path: 'companies',
data: {
breadcrumb: 'Companies'
}
children: [{
path: '', //url: .../companies
component: CompaniesComponent,
} {
path: 'add', //url: .../companies/add
component: FormCompanyComponent,
data: {
breadcrumb: 'Add Company' //This will be "Companies > Add Company"
}
}, {
path: ':id', //url: .../companies/5
component: CompanyComponent
data: {
breadcrumb: 'Company Details' //This will be "Companies > Company Details"
}
}
]
];
You will need to modify the breadcrumb dynamically to change "Company Details" with the actual company name.